November 30, 2007
Please Post Your Answer to Worked Example 4.3
Please Post Your Answer to Worked Example 4.3 here.
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Please Post Your Answer to Worked Example 4.3 here.
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Group E
HW HWout =1.47m
HW100 : HWin = 1.77m > HWout =1.62m
group B answer
using pipe culvert
D=2.275m
for Q 50yr HW= 1.92m
for Q 100yr HW= 2.00m
group B answer revised
using pipe culvert
D=2.275m
outlet control
for Q 50yr HW= 1.92m
for Q 100yr HW= 2.00m
Proposed 2nos 1.5m dia. pipe culvert
For Q50 = 7.00m3/s ; HWi =1.5m > HWo = 1.37m (Inlet Control)
For Q50 = 8.20m3/s ; HWi =1.8m > HWo = 1.66m (Inlet Control)
HW (provided) = 1.8m < HW (required) = 2m
Group E (Revised)
HwHwout =1.47m
Hw100: Hwin = 1.77m > Hwout=1.62m
Therefore inlet control
Group A
Prposed twin pipe culvert 1.5m diameter with inlet control
Group A
Proposed twin pipe culvert 1.5m diameter with inlet control
Group E(from GHD office)
Control HW < 3m
Proposed Box Culvert: 4.5m x1.5m
For Q50: HW inlet=2.37m,outlet=2.24m
For Q100: HW inlet=2.7m , outlet=2.59m
Therefore INLET CONTROL
ABOVE ANSWER ACTUALLY FOR 4.2
Group E(from GHD office)
Control HW < 2m
Proposed Pipe Culvert: 1.5m (2 nos)
For Q50: HW inlet=1.53m,outlet=1.47m
For Q100: HW inlet=1.77m , outlet=1.62m
Therefore INLET CONTROL